WebJan 5, 2024 · ERROR 1052 (23000): Column 'id' in field list is ambiguous 이럴때는 칼럼명앞에 table명.칼럼명을 적어주면 된다. mysql> SELECT topic.id, title, description, created, name, profile FROM topic LEFT JOIN author ON topic.author_id = author.id; topic 테이블의 id칼럼명을 다른 것으로 변경시켜 보여줄 수 도 있다. WebJun 22, 2024 · Solution 1. In your query, the column "worker_name" exists in two tables; in this case, you must reference the tablename as part of the column identifer. SELECT * FROM WORKERS INNER JOIN BOOKING …
Column
WebAug 29, 2024 · SELECT user_name, can.candidate_id FROM user AS usr INNER JOIN candidate as can ON usr.user_id = can.entered_by INNER JOIN candidate_joborder as … WebSQL 错误 [1052] [23000]: Column 's_id' in field list is ambiguous. 时间:2024-03-07 12:37:25 浏览:6. 这个问题是关于 SQL 的,我可以回答。这个错误是因为在查询语句 … kiwirrkurra council aboriginal corporation
fix-sequelize-ts: SequelizeDatabaseError: Column
WebSQL 错误 [1052] [23000]: Column 's_id' in field list is ambiguous. 时间:2024-03-07 12:37:25 浏览:6. 这个问题是关于 SQL 的,我可以回答。这个错误是因为在查询语句中,s_id 这个字段在多个表中都存在,导致无法确定具体使用哪个表中的 s_id 字段。 ... column in field list is ambiguous WebMay 9, 2024 · 0. In first create view you have two id and using * the result is ambigous. In the second create view try using a simple column name alias. create view checkd as ( select wms.id as idWMS , wms.pcode as pcodeWMS , wms.barcode as barcodeWMS from wms join outerb on wms.barcodeWMS = concat ('0', outerb.barcode)); Share. Improve … WebJul 5, 2024 · It means that both tables in the query have the column user_id. You need to specify which one you want to get in the SELECT statement like SELECT username, … rectus abdominis strengthening exercises