WebSep 19, 2024 · Just making it simple for You in your way with 1 loop: for _ in range (4): html = urllib.request.urlopen (url).read () #open url soup = BeautifulSoup (html, 'html.parser') #parse through BeautifulSoup tag = soup ('a') [2] url = tag.get ('href', None) print (url) Share Improve this answer Follow answered Sep 19, 2024 at 12:11 Samprit Sarkar Webprint ("Retrieving",url) tags = soup ('a') for i in range (int (count)): links = [] for tag in tags: links.append (str (tag.get ('href', None))) html = urllib.request.urlopen (links [int (position)-1], context=ctx).read () soup = BeautifulSoup (html, 'html.parser') print ("Retrieving",links [int (position)-1]) tags = soup ('a')
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WebPY4E - Python for Everybody Python for Everybody This web site is building a set of free materials, lectures, book and assignments to help students learn how to program in … WebMar 28, 2024 · Write a Python script that starts with the attached (and now familiar) reviews.csv file and, after replacing the -1 values by pandas Nan (as you had done in Assignment 4), prints the following multi-i … WebMar 29, 2024 · if you notice the end of the link is the number 1488. I am trying to break it up where I can have a for loop that loops from 50 to about 5000 because there are multiple … diy wood staining with coffee