Web⇒ If in a race of 80m, A covers the distance in 20 seconds and B in 25 seconds, then A beats B by: 20m 16m 11m 10m ⇒ The speeds of Daniel and Robert are in the ratio 3:4. In a 300 … WebFeb 21, 2024 · According to the question, when A covers the distance of 200 metes B covers only 200 - 20 = 180 meters Again, in 100 meter race, B beats C by 5 meters. Hence, if B runs 100 metres, C runs 100 - 5 = 95 metres Calculation ∵ If B runs 100 m, C runs = 95 m ∴ If B runs 180 m, C runs = (95/100)× 180 C runs = 171 m ∴ A : B : C = 200 : 180 : 171

[Solved] In a 200 metre race, A beats B by 20 metres, while

WebB beats C by 15 seconds and when B finished the race C is 100 meters away from the finishing mark. This means that C covered the distance of 100 meters in 15 seconds. So … WebSolution: When A covers distance of 800 m, B covers distance of (800 – 80) = 720 m ⇒ Speed of A : Speed of B = 800:720 = 10:9 Also, when B covers distance of 600 m, C covers … how to store raw shelled walnuts

In a Km race A beats B by 100 m and C by 200 m. By how many

WebAns: From above, A and B speeds are in the ratio = 1 2 3 : 1 or 5 : 3. A gives B a start of 80 meters, then B is already 80 meters ahead of A. But we know that A covers 2 meters more for every second. To cover 80 meters he need 40 … WebTherefore, accordingly speed of B will be 9m/s. Now time taken by B to complete the race of 100m will be: =>100/9=11.1sec Now in 11.1sec C has covered 80m as C is defeated by 20m. Speed of C=80/11.1 = 7.207m/s. Since A has covered his race in 10sec (100m/10m/s). Therefore distance covered by C in 10 sec = 7.207x10 = 72.07m or 72m. WebIn a Km race A can beat B by 80 m and B can beat C by 60 m. In the same race, A can beat C by : Options A. 135.2 m B. 130.5 m C. 142 m D. 132.5 m Correct Answer 135.2 m … how to store raw turnips